Solve the system by the method of substitution. $\left\{ \begin{array} { l }
y = - 4 x \
y = x ^ { 3 } + x ^ { 2 } - x
\end{array} \right.$
A)(3, 4)
B)(0, 3)
C)(3, 4), (-3, -4)
D)No real solution
E)(0, 0)

Question

Solve the system by the method of substitution.  $\left\{ \begin{array} { l } 
y = - 4 x \
y = x ^ { 3 } + x ^ { 2 } - x
\end{array} \right.$  
A)(3, 4)
B)(0, 3)
C)(3, 4), (-3, -4)
D)No real solution
E)(0, 0)

Quizplus · Accepted Answer

Substitute $y = -4x$ into the second equation: $-4x = x^3 + x^2 - x$. Simplifying gives $x^3 + x^2 + 3x = 0$. Factoring out $x$, we get $x(x^2 + x + 3) = 0$. The only real solution is $x = 0$, which gives $y = 0$. Thus, the solution is (0, 0).

Solve the System by the Method of Substitution {y=−4xy=x3+x2−x\left\{ \begin{array} { l } y = - 4 x \\y = x ^ { 3 } + x ^ { 2 } - x\end{array} \right.{y=−4xy=x3+x2−x​

Solve the System by the Method of Substitution $\left\{ \begin{array} { l } y = - 4 x \\y = x ^ { 3 } + x ^ { 2 } - x\end{array} \right.$