TABLE 8-13
A university wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A surveyed of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "yes" and 1,456 answered "no."
-Referring to Table 8-13, it is possible that the 99% confidence interval calculated from the data will not contain the proportion of student population who feel comfortable reporting cheating by their fellow students.

Question

Quizplus · Accepted Answer

Since the sample size is large enough (n=2,800), we can assume normal distribution and use the z-distribution for the confidence interval. With a sample proportion of 0.48 (1344/2800), the margin of error for a 99% confidence interval is 0.021. This means the interval would be [0.459, 0.501]. It's possible that the true proportion of the student population who feel comfortable reporting cheating by their fellow students is outside of this interval and therefore not captured by the sample data.

TABLE 8-13 A University Wanted to Find Out the Percentage of Students