TABLE 18-8
Recently, a university switched to a new type of computer-based registration. The registrar is concerned with the amount of time students are spending on the computer registering under the new system. She decides to randomly select 8 students on each of the 12 days of the registration and determine the time each spends on the computer registering. The range, mean, and standard deviation of the times required to register are in the table that follows.
$$\begin{array} { c c l l }
\text { Day } & \text { Range } & \text { Mean } & \text { Std.Dev. } \
1 & 10 & 5.250 & 3.4949 \
2 & 31 & 15.250 & 10.3060 \
3 & 13 & 20.375 & 4.9262 \
4 & 21 & 22.875 & 8.3911 \
5 & 35 & 8.500 & 11.3767 \
6 & 18 & 7.875 & 6.9372 \
7 & 25 & 11.250 & 8.5815 \
8 & 30 & 7.875 & 9.5235 \
9 & 17 & 10.250 & 6.3640 \
10 & 22 & 9.500 & 7.8740 \
11 & 27 & 7.875 & 8.7086 \
12 & 26 & 12.875 & 9.3723
\end{array}$$
-Referring to Table 18-8, an R chart is to be constructed for the time required to register. One way to create the lower control limit involves multiplying the average of the sample ranges by D3. For this data set, the value of D3 is _____ .

Question

TABLE 18-8
 Recently, a university switched to a new type of computer-based registration. The registrar is concerned with the amount of time students are spending on the computer registering under the new system. She decides to randomly select 8 students on each of the 12 days of the registration and determine the time each spends on the computer registering. The range, mean, and standard deviation of the times required to register are in the table that follows.
 $$\begin{array} { c c l l } 
\text { Day } & \text { Range } & \text { Mean } & \text { Std.Dev. } \
1 & 10 & 5.250 & 3.4949 \
2 & 31 & 15.250 & 10.3060 \
3 & 13 & 20.375 & 4.9262 \
4 & 21 & 22.875 & 8.3911 \
5 & 35 & 8.500 & 11.3767 \
6 & 18 & 7.875 & 6.9372 \
7 & 25 & 11.250 & 8.5815 \
8 & 30 & 7.875 & 9.5235 \
9 & 17 & 10.250 & 6.3640 \
10 & 22 & 9.500 & 7.8740 \
11 & 27 & 7.875 & 8.7086 \
12 & 26 & 12.875 & 9.3723
\end{array}$$
-Referring to Table 18-8, an R chart is to be constructed for the time required to register. One way to create the lower control limit involves multiplying the average of the sample ranges by D3. For this data set, the value of D3 is _____ .

Quizplus · Accepted Answer

The Answer of  TABLE 18-8
 Recently, a university switched to a new type of computer-based registration. The registrar is concerned with the amount of time students are spending on the computer registering under the new system. She decides to randomly select 8 students on each of the 12 days of the registration and determine the time each spends on the computer registering. The range, mean, and standard deviation of the times required to register are in the table that follows.
 $$\begin{array} { c c l l } 
\text { Day } & \text { Range } & \text { Mean } & \text { Std.Dev. } \
1 & 10 & 5.250 & 3.4949 \
2 & 31 & 15.250 & 10.3060 \
3 & 13 & 20.375 & 4.9262 \
4 & 21 & 22.875 & 8.3911 \
5 & 35 & 8.500 & 11.3767 \
6 & 18 & 7.875 & 6.9372 \
7 & 25 & 11.250 & 8.5815 \
8 & 30 & 7.875 & 9.5235 \
9 & 17 & 10.250 & 6.3640 \
10 & 22 & 9.500 & 7.8740 \
11 & 27 & 7.875 & 8.7086 \
12 & 26 & 12.875 & 9.3723
\end{array}$$
-Referring to Table 18-8, an R chart is to be constructed for the time required to register. One way to create the lower control limit involves multiplying the average of the sample ranges by D3. For this data set, the value of D3 is _____ .

TABLE 18-8 Recently, a University Switched to a New

TABLE 18-8
Recently, a University Switched to a New