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TABLE 16-11
Business Closures in Laramie, Wyoming from 1989 199310199411199513199619199724199835\begin{array} { l l } 1993 & 10 \\1994 & 11 \\1995 & 13 \\1996 & 19 \\1997 & 24 \\1998 & 35\end{array}

Question 140

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TABLE 16-11
Business closures in Laramie, Wyoming from 1989 to 1994 were:
199310199411199513199619199724199835\begin{array} { l l } 1993 & 10 \\1994 & 11 \\1995 & 13 \\1996 & 19 \\1997 & 24 \\1998 & 35\end{array} Microsoft Excel was used to fit both first-order and second-order autoregressive models, resulting in the following partial outputs:

SUMMARY OUTPUT-2 nd OrderModelCoefficients Intercept 5.77 XVariable 1 0.80 XVariable 2 1.14SUMMARY OUTPUT- 1st OrderModelCoefficientsIntercept4.16X Variable1 1.59\begin{array} { |l c| }\hline\text {SUMMARY OUTPUT-2 nd Order}\\\text {Model}\\&\text {Coefficients}\\ \text { Intercept } & - 5.77 \\ \text { XVariable 1 } & 0.80 \\ \text { XVariable 2 } & 1.14\\\\\text {SUMMARY OUTPUT- 1st Order}\\\text {Model}\\&\text {Coefficients}\\\text {Intercept}&- 4.16\\\underline { \text {X Variable1 }} &1.59\\\hline \end{array}

-Referring to Table 16-11, the value of the MAD for the first-order autoregressive model is_____

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