There is an average of 22.455 employees at 22 office furniture dealers in a major metropolitan area, with a standard deviation of 18.52. Construct a 99 percent confidence interval for the true mean number of full-time employees at office furniture dealers.
A) [11.014, 33.896]
B) [11.275, 33.635]
C) [12.284, 32.626]
D) [12.513, 32.397]
E) [20.072, 24.838]

Question

Quizplus · Accepted Answer

[± ] = [22.455 ± 2.831(18.52/ 4.69)] = [22.455 ± 11.18]
= [11.275, 33.635]

There Is an Average of 22