A random sample of 64 students at a university showed an average age of 25 years and a sample standard deviation of 2 years. The 98% confidence interval for the true average age of all students in the university is
A)20.5 to 26.5
B)24.4 to 25.6
C)23.0 to 27.0
D)20.0 to 30.0

Question

Quizplus · Accepted Answer

The 98% confidence interval is calculated using the formula: mean ± (z * (standard deviation/√n)). Here, the mean is 25, the standard deviation is 2, n is 64, and the z-value for 98% confidence is approximately 2.33. This gives the interval 25 ± (2.33 * (2/√64)) = 24.4 to 25.6.

A Random Sample of 64 Students at a University Showed