If P(A) = 0.48, P(A $\cup$ B) = 0.82, and P(B) = 0.54, then P(A $\cap$ B) =
A)0.3936
B)0.3400
C)0.2000
D)1.0200

Name: If P(A) = 0.48, P(A $\cup$ B) = 0.82, and P(B) = 0.54, then P(A $\cap$ B) = A)0.3936 B)0.3400 C)0.2000 D)1.0200
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Question

Quizplus · Accepted Answer

Using the formula for the union of two events, P(A ∪ B) = P(A) + P(B) - P(A ∩ B), we can solve for P(A ∩ B): 0.82 = 0.48 + 0.54 - P(A ∩ B), which simplifies to P(A ∩ B) = 0.20.

If P(A) = 0 ∪\cup∪ B) = 082, and P(B) = 0

If P(A) = 0 $\cup$ B) = 082, and P(B) = 0