Based on the sample evidence below, we want to test the hypothesis that population A has a larger variance than population B.
$\begin{array}{ll}
&\text { Sample A } & \text { Sample B } \
n&11 & 10 \
s^2&12.1 & 5
\end{array}$
The p-value is approximately

Question

Based on the sample evidence below, we want to test the hypothesis that population A has a larger variance than population B. 
 $\begin{array}{ll}
&\text { Sample A } & \text { Sample B } \
n&11 & 10 \
s^2&12.1 & 5
\end{array}$  
The p-value is approximately

Quizplus · Accepted Answer

The test statistic for comparing two variances is the F-test. The F-statistic is calculated as the ratio of the two sample variances: $ F = \frac{s_A^2}{s_B^2} = \frac{12.1}{5} = 2.42 $. With degrees of freedom $ df_1 = 10 $ and $ df_2 = 9 $, the p-value for this F-statistic is approximately 0.10.

Based on the Sample Evidence Below, We Want to Test Sample A Sample B n1110s212.15\begin{array}{ll}&\text { Sample A } & \text { Sample B } \\n&11 & 10 \\s^2&12.1 & 5\end{array}ns2​ Sample A 1112.1​ Sample B 105​

Based on the Sample Evidence Below, We Want to Test $\begin{array}{ll}&\text { Sample A } & \text { Sample B } \\n&11 & 10 \\s^2&12.1 & 5\end{array}$