It is known that the population variance (σ²) is 144.At 95% confidence, what sample size should be taken so that the margin of error does not exceed 5? A) 22 B) 23 C) 24 D) 25

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Quizplus · Accepted Answer

The margin of error is given by:E = z * (σ / √n)where z is the z-score corresponding to the desired confidence level, σ is the population standard deviation, and n is the sample size.At 95% confidence, the z-score is 1.96. Substituting this value into the equation, along with the given values of σ and E, we get:5 = 1.96 * (144 / √n)Solving for n, we get:n = (1.96 * 144 / 5)^2 = 23.04Since we cannot take a fractional sample size, we round up to the nearest whole number, which is 23.

It Is Known That the Population Variance (σ2) Is 144

It Is Known That the Population Variance (σ²) Is 144