Roth is a computer-consulting firm.The number of new clients that they have obtained each month has ranged from 0 to 6.The number of new clients has the probability distribution that is shown below. $$\begin{array}{l}
\text { Number of }\
\begin{array} { c c }
\text { New Clients } & \text { Probability } \
\hline 0 & 0.05 \
1 & 0.10 \
2 & 0.15 \
3 & 0.35 \
4 & 0.20 \
5 & 0.10 \
6 & 0.05
\end{array}
\end{array}$$
The standard deviation is
A) 1.431
B) 2.047
C) 3.05
D) 21

Question

Roth is a computer-consulting firm.The number of new clients that they have obtained each month has ranged from 0 to 6.The number of new clients has the probability distribution that is shown below. $$\begin{array}{l}
\text { Number of }\
\begin{array} { c c } 
\text { New Clients } & \text { Probability } \
\hline 0 & 0.05 \
1 & 0.10 \
2 & 0.15 \
3 & 0.35 \
4 & 0.20 \
5 & 0.10 \
6 & 0.05
\end{array}
\end{array}$$ 
The standard deviation is
A)  1.431
B)  2.047
C)  3.05
D)  21

Quizplus · Accepted Answer

The standard deviation is 1.431. This can be calculated using the formula:σ = √(Σ(x - μ)^2 * P(x))where x is the number of new clients, μ is the mean, and P(x) is the probability of getting x new clients.The mean is:μ = Σ(x * P(x)) = 0 * 0.05 + 1 * 0.10 + 2 * 0.15 + 3 * 0.35 + 4 * 0.20 + 5 * 0.10 + 6 * 0.05 = 3The variance is:σ^2 = Σ((x - μ)^2 * P(x)) = (0 - 3)^2 * 0.05 + (1 - 3)^2 * 0.10 + (2 - 3)^2 * 0.15 + (3 - 3)^2 * 0.35 + (4 - 3)^2 * 0.20 + (5 - 3)^2 * 0.10 + (6 - 3)^2 * 0.05 = 2.047The standard deviation is:σ = √(σ^2) = √(2.047) = 1.431

Roth Is a Computer-Consulting Firm The Standard Deviation Is A) 1

Roth Is a Computer-Consulting Firm The Standard Deviation Is
A) 1