In estimating the total of a population of size N, where N is very large compared to the sample size, the confidence interval estimator of the total is $N \left[ \bar { x } \pm t _ { \alpha / 2 } \cdot s / \sqrt { n } \right]$ .

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The Answer of In estimating the total of a population of size N, where N is very large compared to the sample size, the confidence interval estimator of the total is $N \left[ \bar { x } \pm t _ { \alpha / 2 } \cdot s / \sqrt { n } \right]$ .

In Estimating the Total of a Population of Size N N[xˉ±tα/2⋅s/n]N \left[ \bar { x } \pm t _ { \alpha / 2 } \cdot s / \sqrt { n } \right]N[xˉ±tα/2​⋅s/n​]

In Estimating the Total of a Population of Size N $N \left[ \bar { x } \pm t _ { \alpha / 2 } \cdot s / \sqrt { n } \right]$