The value of A such that P(-A $\le$ t $\le$ A)= 0.95,where the degrees of freedom are 20,is 2.086.

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This statement is true. The value of 2.086 corresponds to the 95th percentile of the F-distribution with numerator degrees of freedom 3 and denominator degrees of freedom 20. Therefore, setting A equal to 2.086 in the given probability statement ensures that the probability of F1F1F1S1-F1F1F10A being less than or equal to t and F1F1F1S1 being less than or equal to A is 0.95.

The Value of a Such That P(-A ≤\le≤ T ≤\le≤ A)= 095,where the Degrees of Freedom Are 20,is 2

The Value of a Such That P(-A $\le$ T $\le$ A)= 095,where the Degrees of Freedom Are 20,is 2