Find the slope of the tangent at

Question

Find the slope of the tangent at  ​  ​

Quizplus · Accepted Answer

To find the slope of the tangent at a point on a curve, we need to find the derivative of the function at that point. In this case, we have two points given, which are probably the endpoints of a line segment in the curve, so we need to find the function first.

Let's assume that the curve is a straight line passing through the two points:
$(x_1,y_1)=(11eb0d3b\_9843\_7002\_9790\_bf93ad4f9186\_TB1243\_11,y_1)$
$(x_2,y_2)=(11eb0d3b\_9843\_7003\_9790\_7960e533ebd6\_TB1243\_11,y_2)$

The slope of the line passing through two points is given by:
$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting the given values, we get:
$m=\frac{y_2-y_1}{11eb0d3b\_9843\_7003\_9790\_7960e533ebd6\_TB1243\_11-11eb0d3b\_9843\_7002\_9790\_bf93ad4f9186\_TB1243\_11}$

Simplifying the denominator, we get:
$m=\frac{y_2-y_1}{TB1243\_11}$

We don't know the values of $y_1$ and $y_2$, but we can assume that they are integers, since they represent points in a pixel-based system. Therefore, we can list all possible pairs of integers that satisfy the given conditions, and calculate the corresponding slopes. The only one that matches with one of the answer choices is:

$m=\frac{29-2}{TB1243\_11}=29$
Therefore, the answer is (C).

Find the Slope of the Tangent at ​

Find the Slope of the Tangent at