If P(A) = .62, P(B) = .47, and P(A ∪ B) = .88; then P(A ∩ B) =
A) .291
B) 1.970
C) .670
D) .210

Name: If P(A) = .62, P(B) = .47, and P(A ∪ B) = .88; then P(A ∩ B) = A) .291 B) 1.970 C) .670 D) .210
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Question

Quizplus · Accepted Answer

The formula for the probability of the union of two events is P(A ∪ B) = P(A) + P(B) - P(A ∩ B). Plugging in the given values: .88 = .62 + .47 - P(A ∩ B). Solving for P(A ∩ B) gives P(A ∩ B) = .62 + .47 - .88 = .21.