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Haircuts You Need to Find a New Hair Stylist and Know

Question 43

Essay

Haircuts You need to find a new hair stylist and know that there are two terrific salons in your area, Hair by Charles and Curl Up & Dye. You want a really good haircut, but you do not want to pay too much for the cut. A random sample of costs for 10 different stylists was taken at each salon (each salon employs over 100 stylists).
a. Indicate what inference procedure you would use to see if there is a significant difference in the costs for haircuts at each salon. Check the appropriate assumptions and conditions and indicate whether you could or could not proceed. (Do not do the actual test.)
b. A friend tells you that he has heard that Curl Up & Dye is the more expensive salon.
i. Write hypotheses for your friend's claim.
ii. The following are computer outputs. Which output is the correct one to use for this test? Explain.  Output A: \text { Output A: }
 Two-sample T’ for Hair by Charles vs Curl Up & Dye \text { Two-sample T' for Hair by Charles vs Curl Up \& Dye }
 N  Mean  StDev  SE Mean  Hair by Charles 1022.106.332.0 Curl Up E Dye 1026.004.811.5\begin{array}{lrrrr} & \text { N } & \text { Mean } & \text { StDev } & \text { SE Mean } \\\text { Hair by Charles } & 10 & 22.10 & 6.33 & 2.0 \\\text { Curl Up E Dye } & 10 & 26.00 & 4.81 & 1.5\end{array}

Difference = = mu (Hair by Charles) - mu (Curl Up & Dye)
Bstimate for difference: -3.90000
958 CI for difference: ( 9.22983,1.42983) -9.22983,1.42983)
T-Test of difference =0 =0 (vs not = = ): T-Value =1.55 =-1.55 \quad P-Value =0.140 =0.140
DF=16 \mathrm{DF}=16

 Output A: \text { Output A: }
 Paired T for Hair by Charlea - Curl Up & Dye \text { Paired T for Hair by Charlea - Curl Up \& Dye }
N Mean  St.Dev  SB Mean  Hair by Charles 1022.10006.33252.0025 Curl Up & Dye 1026.00004.80741.5202 Difference 103.900007.370362.33071\begin{array}{lrrrr} & {N} & \text { Mean } & \text { St.Dev } & \text { SB Mean } \\\text { Hair by Charles } & 10 & 22.1000 & 6.3325 & 2.0025 \\\text { Curl Up \& Dye } & 10 & 26.0000 & 4.8074 & 1.5202 \\\text { Difference } & 10 & -3.90000 & 7.37036 & 2.33071\end{array}

958 CI for mean difference: (9.17244,1.37244) (-9.17244,1.37244)
T-Test of mean difference =0(vs =0(\mathrm{vs} not =0):T =0): \mathrm{T} -Value =1.67 =-1.67 P-Value = = 0.129
iii. Use the appropriate computer output to make a conclusion about the hypothesis test based on the data. Make sure to state your conclusion in context.

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a. I would use a two-sample t-test for t...

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