Different concentrations of ions on either side of a cell membrane constitute a concentration cell, which is described by the Nernst equation given below. What is the electrochemical potential across a membrane when the sodium ion concentration is 0.10 M on one side of the membrane and 0.010 M on the other side, and the temperature is 37°C (body temperature)?
(Given: Na⁺ + e^- $\rarr$ , $E _ { \mathrm { red } } ^ { 0 }$
= -2.71 V; F = 96,485 C; 1 J = 1 C V; R = 8.315 J / (mol K)) $E = E ^ { \circ } - \frac { R T } { n F } \ln Q$

Question

Different concentrations of ions on either side of a cell membrane constitute a concentration cell, which is described by the Nernst equation given below. What is the electrochemical potential across a membrane when the sodium ion concentration is 0.10 M on one side of the membrane and 0.010 M on the other side, and the temperature is 37°C (body temperature)?
(Given: Na⁺ + e^-

\rarr

,

E _ { \mathrm { red } } ^ { 0 }

= -2.71 V; F = 96,485 C; 1 J = 1 C V; R = 8.315 J / (mol K))

E = E ^ { \circ } - \frac { R T } { n F } \ln Q

Quizplus · Accepted Answer

The Answer of Different concentrations of ions on either side of a cell membrane constitute a concentration cell, which is described by the Nernst equation given below. What is the electrochemical potential across a membrane when the sodium ion concentration is 0.10 M on one side of the membrane and 0.010 M on the other side, and the temperature is 37°C (body temperature)? (Given: Na⁺ + e^- $\rarr$, $E _ { \mathrm { red } } ^ { 0 }$ = -2.71 V; F = 96,485 C; 1 J = 1 C V; R = 8.315 J / (mol K)) $E = E ^ { \circ } - \frac { R T } { n F } \ln Q$

Different Concentrations of Ions on Either Side of a Cell →\rarr→

Different Concentrations of Ions on Either Side of a Cell $\rarr$