The first step in the disintegration of uranium is ${ } _ { 92 } ^ { 238 } \mathrm { U } \rightarrow { } _ { 90 } ^ { 234 } \mathrm { Th }$ . What particle is emitted in this reaction?

Question

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In the given nuclear reaction, uranium-238 decays into thorium-234. This process involves the emission of an alpha particle, which consists of 2 protons and 2 neutrons, reducing the atomic number by 2 and the mass number by 4.

The First Step in the Disintegration of Uranium Is 92238U→90234Th{ } _ { 92 } ^ { 238 } \mathrm { U } \rightarrow { } _ { 90 } ^ { 234 } \mathrm { Th }92238​U→90234​Th

The First Step in the Disintegration of Uranium Is ${ } _ { 92 } ^ { 238 } \mathrm { U } \rightarrow { } _ { 90 } ^ { 234 } \mathrm { Th }$