The enthalpy of fusion for benzene (C₆H₆) is 127.40 kJ/kg, and its melting point is 5.5°C. What is the entropy change when 1 mole of benzene melts at 5.5°C?

Question

Quizplus · Accepted Answer

The entropy change (ΔS) can be calculated using the formula ΔS = ΔH/T, where ΔH is the enthalpy change and T is the temperature in Kelvin. First, convert the enthalpy of fusion from kJ/kg to J/mol using the molar mass of benzene (78.11 g/mol), then convert the temperature to Kelvin (5.5°C = 278.65 K). Calculate ΔS = (127.40 kJ/kg * 78.11 g/mol * 1000 J/kJ) / 278.65 K = 35.7 J/K.

The Enthalpy of Fusion for Benzene (C6H6) Is 127

The Enthalpy of Fusion for Benzene (C₆H₆) Is 127