Determine the value of $\Delta$G° for the reaction 2NO₂(g) $\leftrightarrow$N₂O₄(g) Given $ \begin{array}{lcr} Substance&&S^{\circ}(\mathrm{J} /(\mathbf{m o l} \cdot \mathbf{K}))\ & \Delta \boldsymbol{H}_{\mathbf{f}}^{\circ} & \ & (\mathbf{k J} / \mathbf{m o l}) & \ \mathrm{NO}_{2}(g) & 33.2 & 240.0 \ \mathrm{~N}_{2} \mathrm{O}_{4}(g) & 9.2 & 304.2\end{array} $

Question

Quizplus · Accepted Answer

$\Delta$G° = -RTlnK = -RTln($ \frac{a_{N_2O_4}}{a_{NO_2}^2}$) = -RTln($ \frac{P_{N_2O_4}}{P_{NO_2}^2}$) = -RTln($ \frac{1}{K_p}$)$K_p$ = $ \frac{P_{N_2O_4}}{P_{NO_2}^2}$ = $ \frac{e^{-\Delta G^{\circ}/RT}}{e^{2\Delta G^{\circ}/RT}}$ = $ e^{-\Delta G^{\circ}/RT}$$\Delta$G° = -RTln$K_p$ = -8.314 J/(mol·K) × 298 K × ln(0.092) = -4800 J = -4.8 kJ

Determine the Value Of Δ\DeltaΔ G° for the Reaction 2NO2(g) ↔\leftrightarrow↔ N2O4(g) Given

Determine the Value Of $\Delta$ G° for the Reaction
2NO₂(g) $\leftrightarrow$ N₂O₄(g)
Given