The Equilibrium Constant for the Formation of Calcium Carbonate from the Ions

The equilibrium constant for the formation of calcium carbonate from the ions in solution is
2.2 * 10⁸ according to the reaction:
Ca²⁺(aq) + CO₃^2-(aq) $\leftrightarrows$
CaCO₃(s)
What is the value of the equilibrium constant for the reverse of this reaction?

A) the same, 2.2 *10⁸
B) -2.2 * 10⁸
C) 2.2 *10^-8
D) 4.5 * 10^-9
E) 4.5 * 10⁹