The second-order reaction A $\rightarrow$ B is found to have a rate constant of 0.978 M^-¹s^-¹. What is the half-life of this reaction when [A]₀ = 0.0300 M?

Name: The second-order reaction A $\rightarrow$ B is found to have a rate constant of 0.978 M - 1 s - 1 . What is the half-life of this reaction when [A] 0 = 0.0300 M?
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Question

Quizplus · Accepted Answer

The half-life of a second-order reaction is given by t_1/2 = 1/(k[A]₀). Substituting the given values, we get t_1/2 = 1/(0.978 M^-¹s^-¹ x 0.0300 M) = 34.1 s.

The Second-Order Reaction A →\rightarrow→ B Is Found to Have a Rate Constant of 0

The Second-Order Reaction A $\rightarrow$ B Is Found to Have a Rate Constant of 0