The energy content of a Big Mac is 540 Cal. How much water can be heated from 20°C to 90°C by this amount of energy? (c_P(water) = 1.00 g/mL, c_s(water) = 4.18 J/(g . °C) ,
1 Cal = 1,000 cal = 4.184 kJ)

Question

Quizplus · Accepted Answer

The energy in a Big Mac is 540,000 cal (since 1 Cal = 1,000 cal). Using the formula q = mcΔT, where q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change, we can solve for m. The temperature change ΔT is 70°C (90°C - 20°C). Rearranging the formula gives m = q / (cΔT). Substituting the values, m = 540,000 cal / (1 cal/g°C * 70°C) = 7,714.29 g. Since the density of water is 1 g/mL, this is equivalent to 7,714.29 mL or approximately 7.7 L.

The Energy Content of a Big Mac Is 540 Cal