Determine the change in enthalpy for the following reaction from the enthalpies of formation for the reactants and products.
(C₂H₂Cl₂, +4.27 kJ/mol; C₂H₂Cl₄, -155.6 kJ/mol)
Cl₂(g) + C₂H₂Cl₂(g) $\rightarrow$ C₂H₂Cl₄(g)

Question

Determine the change in enthalpy for the following reaction from the enthalpies of formation for the reactants and products.
(C₂H₂Cl₂, +4.27 kJ/mol; C₂H₂Cl₄, -155.6 kJ/mol)
Cl₂(g) + C₂H₂Cl₂(g)

\rightarrow

C₂H₂Cl₄(g)

Quizplus · Accepted Answer

The change in enthalpy (ΔH) for the reaction is calculated using the formula: ΔH = ΣΔHf(products) - ΣΔHf(reactants). For this reaction, ΔH = (-155.6 kJ/mol) - (+4.27 kJ/mol) = -159.87 kJ/mol, which rounds to -159.9 kJ/mol.

Determine the Change in Enthalpy for the Following Reaction from the Enthalpies