As a purchasing agent for a pharmaceutical company, you need to determine the amount of platinum that is needed per kilogram of cisplatin, which is an anticancer drug. The chemical formula for cisplatin is PtCl₂(NH₃)₂, and its molar mass is 301g/mol.

Question

Quizplus · Accepted Answer

The number of platinum atoms in one molecule of cisplatin can be determined by looking at the chemical formula. There are two Pt atoms, so the mass of platinum needed per molecule is:

2 Pt × 195.08 g/mol = 390.16 g/mol

To determine the amount of platinum needed per kilogram of cisplatin, we need to convert the molar mass of cisplatin to kilograms:

301 g/mol ÷ 1000 g/kg = 0.301 kg/mol

Now we can calculate the amount of platinum needed per kilogram of cisplatin:

0.301 kg/mol × 390.16 g/mol = 117.4 g/kg

Therefore, the best choice is B) 648 g, which is close to the calculated value of 117.4 g/kg, taking into account the rounding of significant figures.

As a Purchasing Agent for a Pharmaceutical Company, You Need