The average atomic mass of zinc is 65.39 amu. Given the data in the following table, what is the natural abundance of ⁶⁶Zn? $$\begin{array} { c c c } \text { Isotope } & \text { Mass (amu) } & \text { Natural Abundance (\%) } \ { } ^ { 64 } \mathrm { Zn } & 63.9291 & 48.89 \ { } ^ { 66 } \mathrm { Zn } & 65.9260 & ? \ { } ^ { 67 } \mathrm { Zn } & 66.9271 & 4.11 \ { } ^ { 68 } \mathrm { Zn } & 67.9249 & 18.56 \ { } ^ { 70 } \mathrm { Zn } & 69.9253 & 0.62 \end{array}$$

Question

Quizplus · Accepted Answer

The average atomic mass of zinc is 65.39 amu. This means that the weighted average of the masses of the isotopes of zinc, taking into account their natural abundances, is 65.39 amu. The average atomic mass can be calculated using the following formula:Average atomic mass = (mass of isotope 1 x natural abundance of isotope 1) + (mass of isotope 2 x natural abundance of isotope 2) + ...Substituting the values from the table into the formula, we get:65.39 amu = (63.9291 amu x 48.89%) + (65.9260 amu x natural abundance of 66Zn) + (66.9271 amu x 4.11%) + (67.9249 amu x 18.56%) + (69.9253 amu x 0.62%)Solving for the natural abundance of 66Zn, we get:Natural abundance of 66Zn = 27.83%Therefore, the correct answer is A) 27.83%.

The Average Atomic Mass of Zinc Is 65 A) 2783% B) 0

The Average Atomic Mass of Zinc Is 65 A) 2783%
B) 0