Starting with the identity $\sin ^ { 2 } x + \cos ^ { 2 } x = 1$ and then dividing both sides of the equation by a suitable trigonometric function, derive the trigonometric identity.
$\sec ^ { 2 } x = 1 + \tan ^ { 2 } x$

Question

Starting with the identity $\sin ^ { 2 } x + \cos ^ { 2 } x = 1$ and then dividing both sides of the equation by a suitable trigonometric function, derive the trigonometric identity.
​ $\sec ^ { 2 } x = 1 + \tan ^ { 2 } x$

Quizplus · Accepted Answer

The Answer of Starting with the identity $\sin ^ { 2 } x + \cos ^ { 2 } x = 1$ and then dividing both sides of the equation by a suitable trigonometric function, derive the trigonometric identity.
​ $\sec ^ { 2 } x = 1 + \tan ^ { 2 } x$

Starting with the Identity sin⁡2x+cos⁡2x=1\sin ^ { 2 } x + \cos ^ { 2 } x = 1sin2x+cos2x=1

Starting with the Identity $\sin ^ { 2 } x + \cos ^ { 2 } x = 1$