The Soap Bubble I Am Blowing Has a Radius That $S = 4 \pi r ^ { 2 }$

The soap bubble I am blowing has a radius that is growing at a rate of 3 cm/s. How fast is the surface area growing when the radius is 10 cm (The surface area of a sphere of radius r is $S = 4 \pi r ^ { 2 }$ .)

A) $\frac { \mathrm { d } S } { \mathrm {~d} t } = 85 \pi \frac { \mathrm { cm } ^ { 2 } } { \mathrm {~s} }$
B) $\frac { \mathrm { d } S } { \mathrm {~d} t } = \frac { 240 } { \pi } \frac { \mathrm { cm } ^ { 2 } } { \mathrm {~s} }$
C) $\frac { \mathrm { d } S } { \mathrm {~d} t } = 240 \pi \frac { \mathrm { cm } ^ { 2 } } { \mathrm {~s} }$
D) $\frac { \mathrm { d } S } { \mathrm {~d} t } = 243 \pi \frac { \mathrm { cm } ^ { 2 } } { \mathrm {~s} }$
E) $\frac { \mathrm { d } S } { \mathrm {~d} t } = 24 \pi \frac { \mathrm { cm } ^ { 2 } } { \mathrm {~s} }$