A local newspaper that appears six days per week wanted to forecast two-day revenues from its business services classified ads section. The revenues (in $1000s) were recorded for the past 52 weeks. From these data, the following regression equation was computed: $= 2000 + 0.6 t - 150 D _ { 1 } - 40 D _ { 2 }$ , t = 1, 2, 3,…156,
where: $D _ { 1 }$ = 1, if Monday or Tuesday
= 0, otherwise. $D _ { 2 }$ = 1, if Wednesday or Thursday
= 0, otherwise.
Forecast the two-day revenues for the next week.

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The Answer of A local newspaper that appears six days per week wanted to forecast two-day revenues from its business services classified ads section. The revenues (in $1000s) were recorded for the past 52 weeks. From these data, the following regression equation was computed: $= 2000 + 0.6 t - 150 D _ { 1 } - 40 D _ { 2 }$ , t = 1, 2, 3,…156,
where: $D _ { 1 }$ = 1, if Monday or Tuesday
= 0, otherwise. $D _ { 2 }$ = 1, if Wednesday or Thursday
= 0, otherwise.
Forecast the two-day revenues for the next week.

A Local Newspaper That Appears Six Days Per Week Wanted =2000+0.6t−150D1−40D2= 2000 + 0.6 t - 150 D _ { 1 } - 40 D _ { 2 }=2000+0.6t−150D1​−40D2​

A Local Newspaper That Appears Six Days Per Week Wanted $= 2000 + 0.6 t - 150 D _ { 1 } - 40 D _ { 2 }$