One-way ANOVA is performed on independent samples taken from three normally distributed populations with equal variances. The following summary statistics are calculated: $n _ { 1 } =$ 6, $\bar { x } _ { 1 } =$ 50, $s _ { 1 } =$ 5.2. $n _ { 2 } =$ 8, $\bar { x } _ { 2 } =$ 55, $S _ { 2 } =$ 4.9 . $n _ { 3 } =$ 6, $\bar { x } _ { 3 } =$ 51, $s _ { 3 } =$ 5.4. The grand mean equals:
A) 50.0.
B) 52.0.
C) 52.3.
D) 53.0.

Question

Quizplus · Accepted Answer

To find the grand mean, we need to take the average of all the sample means. Thus, the grand mean is (50 + 55 + 51)/3 = 52.0.

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