If P(A) = 0.60, P(B) = 0.58, and P(A $\cup$ B) = 0.70, then P(A $\cap$\ B) is: $$\begin{array} { | l | l | }
\hline \text { A. } & 0.60 . \
\hline \text { B. } & 0.70 . \
\hline \text { C. } & 0.48 . \
\hline \text { D. } & 0.58 . \
\hline
\end{array}$$

Question

If P(A) = 0.60, P(B) = 0.58, and P(A $\cup$ B) = 0.70, then P(A $\cap$\ B) is: $$\begin{array} { | l | l | } 
\hline \text { A. } & 0.60 . \
\hline \text { B. } & 0.70 . \
\hline \text { C. } & 0.48 . \
\hline \text { D. } & 0.58 . \
\hline
\end{array}$$

Quizplus · Accepted Answer

The Answer of If P(A) = 0.60, P(B) = 0.58, and P(A $\cup$ B) = 0.70, then P(A $\cap$\ B) is: $$\begin{array} { | l | l | } 
\hline \text { A. } & 0.60 . \
\hline \text { B. } & 0.70 . \
\hline \text { C. } & 0.48 . \
\hline \text { D. } & 0.58 . \
\hline
\end{array}$$

If P(A) = 0 ∪\cup∪ B) = 070, Then P(A ∩\cap∩ \ B) Is

If P(A) = 0 $\cup$ B) = 070, Then P(A $\cap$ \ B) Is