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Mark and His Friends Are Planning for a Holiday Party

Question 48

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Mark and his friends are planning for a holiday party. Data on longitude, latitude, and number of friends at each of the 10 locations are given below. Mark would like to identify the location for the holiday party such that it minimizes the demand-weighted distance, where demand is the number of friends at each location. Find the optimal location for the party. The distance between two cities can be approximated by the following formula. 50( lat 1 lat 2)2+( long 1 long 2)250 \sqrt { \left( \text { lat } _ { 1 } - \text { lat } _ { 2 } \right) ^ { 2 } + \left( \text { long } _ { 1 } - \text { long } _ { 2 } \right) ^ { 2 } } where lat1 and long1 are the latitude and longitude of city 1, and lat2 and long2 are the latitude and longitude of city 2. (Hint: Notice that all longitude values given for this problem are negative. Make sure that you do not check the option for Make Unconstrained Variables Non-Negative in Solver.)  Location  latitude  longitude  Friends  Ohio 26.78277.63912 TN 38.95276.1642 Mass 36.96185.9211 Iowa 33.21681.7538 New York 36.49984.57510 Virginia 44.93472.7987 NJ 40.85076.6575 Wyoming 42.90175.5146 Maryland 41.019120.4911 CA 43.623119.6269\begin{array} { l | c | c | c } \text { Location } & \text { latitude } & \text { longitude } & \text { Friends } \\\hline \text { Ohio } & 26.782 & - 77.639 & 12 \\\text { TN } & 38.952 & - 76.164 & 2 \\\text { Mass } & 36.961 & - 85.921 & 1 \\\text { Iowa } & 33.216 & - 81.753 & 8 \\\text { New York } & 36.499 & - 84.575 & 10 \\\text { Virginia } & 44.934 & - 72.798 & 7 \\\text { NJ } & 40.850 & - 76.657 & 5 \\\text { Wyoming } & 42.901 & - 75.514 & 6 \\\text { Maryland } & 41.019 & - 120.491 & 1 \\\text { CA } & 43.623 & - 119.626 & 9\end{array}

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