Assuming that the heights of college women are normally distributed with mean 66 inches and standard deviation 2 inches, what percentage of women are shorter than 72 inches?
A)99.9%
B)0.1%
C)97.7%
D)2.3%
E)15.9%

Question

Quizplus · Accepted Answer

To find the percentage of women shorter than 72 inches, we calculate the Z-score: $Z = \frac{X - \mu}{\sigma} = \frac{72 - 66}{2} = 3$. A Z-score of 3 corresponds to a percentile just below 99.9%, meaning approximately 99.9% of women are shorter than 72 inches.

Assuming That the Heights of College Women Are Normally Distributed