If C(x) =8x+ 1,000 and $\mathrm { A } ( x ) = \frac { C ( x ) } { x }$ R(x) =$20x, and P(x) = R(x) - C(x), then if x = 200, P(x)

A)1,600
B)1,200
C)1,400
D)1,800

Name: If C(x) =8x+ 1,000 and $\mathrm { A } ( x ) = \frac { C ( x ) } { x }$ R(x) =$20x, and P(x) = R(x) - C(x), then if x = 200, P(x) A)1,600 B)1,200 C)1,400 D)1,800
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Question

If C(x) =8x+ 1,000 and $\mathrm { A } ( x ) = \frac { C ( x ) } { x }$  R(x) =$20x, and P(x) = R(x) - C(x), then if x = 200, P(x)

A)1,600
B)1,200
C)1,400
D)1,800

Quizplus · Accepted Answer

The Answer of If C(x) =8x+ 1,000 and $\mathrm { A } ( x ) = \frac { C ( x ) } { x }$  R(x) =$20x, and P(x) = R(x) - C(x), then if x = 200, P(x)

A)1,600
B)1,200
C)1,400
D)1,800

If C(x) =8x+ 1,000 And A(x)=C(x)x\mathrm { A } ( x ) = \frac { C ( x ) } { x }A(x)=xC(x)​

If C(x) =8x+ 1,000 And $\mathrm { A } ( x ) = \frac { C ( x ) } { x }$