$$\text { If } Z = \sqrt { R ^ { 2 } + X ^ { 2 } } \text {, where } R = 1,500 \text { and } X = 2,200 \text {, then } Z =$$
A)3,700
B)2,663
C)6,363
D)892

Question

Quizplus · Accepted Answer

Z is calculated using the Pythagorean theorem in this context, where Z is the hypotenuse and R and X are the other two sides of a right triangle. Plugging in the given values, $Z = \sqrt{1500^2 + 2200^2} = \sqrt{2250000 + 4840000} = \sqrt{7090000} \approx 2663$.

If Z=R2+X2, where R=1,500 and X=2,200, then Z=\text { If } Z = \sqrt { R ^ { 2 } + X ^ { 2 } } \text {, where } R = 1,500 \text { and } X = 2,200 \text {, then } Z = If Z=R2+X2​, where R=1,500 and X=2,200, then Z=

$\text { If } Z = \sqrt { R ^ { 2 } + X ^ { 2 } } \text {, where } R = 1,500 \text { and } X = 2,200 \text {, then } Z =$