What is the percent efficiency (E)of an engine if the input (I)is 20,000 calories and the output (P)is 6,200 calories? Use the formula: $$E = \frac { I - P } { I }$$
A)1.45
B)0.69
C)2.23
D)0.45

Name: What is the percent efficiency (E)of an engine if the input (I)is 20,000 calories and the output (P)is 6,200 calories? Use the formula: \[E = \frac { I - P } { I }\] A)1.45 B)0.69 C)2.23 D)0.45
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Quizplus · Accepted Answer

Plug in the values into the formula to get E = (20000-6200)/20000 = 0.69 or 69%.

What Is the Percent Efficiency (E)of an Engine If the Input