Solve $a ^ { 2 } + b ^ { 2 } = c ^ { 2 }$ for b.
A) $b = \sqrt { a ^ { 2 } - c ^ { 2 } }$
B) $b = \sqrt { c ^ { 2 } - a ^ { 2 } }$
C) $b = a ^ { 2 } - c ^ { 2 }$
D) $b = c ^ { 2 } - a ^ { 2 }$

Question

Quizplus · Accepted Answer

Subtracting $a ^ { 2 }$ from both sides gives $b ^ { 2 } = c ^ { 2 } - a ^ { 2 }$. Taking the positive square root of both sides gives the solution for b as $b = \sqrt { c ^ { 2 } - a ^ { 2 } }$.

Solve a2+b2=c2a ^ { 2 } + b ^ { 2 } = c ^ { 2 }a2+b2=c2

Solve $a ^ { 2 } + b ^ { 2 } = c ^ { 2 }$