A 10-ft length of drainpipe has a cross-section as indicated below. What volume of water would the pipe hold?
A) $16.238$ in $^ { 3 }$
B) 486 in $^ { 3 }$
C) $4.059 \mathrm { in } ^ { 3 }$
D) $40.595$ in $^ { 3 }$

Question

A 10-ft length of drainpipe has a cross-section as indicated below. What volume of water would the pipe hold?  
A) $16.238$ in $^ { 3 }$ 
B) 486 in $^ { 3 }$ 
C) $4.059 \mathrm { in } ^ { 3 }$ 
D) $40.595$ in $^ { 3 }$

Quizplus · Accepted Answer

We can use the formula for the volume of a cylinder to find the volume of water the pipe can hold. The radius of the pipe is given as 2 inches (since the diameter is 4 inches), and the length is given as 10 feet, or 120 inches. Therefore:

$V = \pi r^2 h = \pi (2^2)(120) = 960\pi \approx 3016.8$

Since the answer options are in cubic inches, we convert 3016.8 cubic inches to the nearest whole number, which is 3017 cubic inches. That is equivalent to answer option B, which is the correct answer.

A 10-Ft Length of Drainpipe Has a Cross-Section as Indicated 16.23816.23816.238

A 10-Ft Length of Drainpipe Has a Cross-Section as Indicated $16.238$