Factor the special product: $x ^ { 2 } - 36 y ^2$

Question

Quizplus · Accepted Answer

This is a difference of squares special product since $x^2$ is a perfect square and $36y^2 = (6y)^2$ is also a perfect square. Using the formula for the difference of squares, we get $(x^2 - 36y^2) = (x+6y)(x-6y)$, so the correct answer is B. Answer choices A and D are incorrect because they both involve the square of a binomial, which is not what we have in this case. Answer choice C is incorrect because it does not involve the difference of two squares.

Factor the Special Product x2−36y2x ^ { 2 } - 36 y ^2x2−36y2

Factor the Special Product $x ^ { 2 } - 36 y ^2$