Factor completely: $x ^ { 2 } - 4 x + 4$
A) $4 \left( x ^ { 2 } - x + 1 \right)$
B) $( x - 2 ) ^ { 2 }$
C) (x +2)(x-2)
D) $( x + 2 ) ^ { 2 }$

Name: Factor completely: $x ^ { 2 } - 4 x + 4$ A) $4 \left( x ^ { 2 } - x + 1 \right)$ B) $( x - 2 ) ^ { 2 }$ C) (x +2)(x-2) D) $( x + 2 ) ^ { 2 }$
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Question

Factor completely: $x ^ { 2 } - 4 x + 4$
A) $4 \left( x ^ { 2 } - x + 1 \right)$ 
B) $( x - 2 ) ^ { 2 }$ 
C) (x +2)(x-2) 
D) $( x + 2 ) ^ { 2 }$

Quizplus · Accepted Answer

This is a perfect square trinomial of the form $(a-b)^2 = a^2 - 2ab + b^2$ where $a=x$ and $b=2$. So we have $(x-2)^2 = x^2 - 2 \cdot x \cdot 2 + 2^2 = x^2 - 4x + 4$.

Factor Completely x2−4x+4x ^ { 2 } - 4 x + 4x2−4x+4

Factor Completely $x ^ { 2 } - 4 x + 4$