$$\text { Solve the system of equations by graphing: } \left\{ \begin{array} { c }
x - 2 y = 6 \
- 2 x + 4 y = - 12
\end{array} \right.$$ I.

II.

III.

IV.

A)I
B)II
C)III
D)IV

Question

$$\text { Solve the system of equations by graphing: } \left\{ \begin{array} { c } 
x - 2 y = 6 \
- 2 x + 4 y = - 12
\end{array} \right.$$ I.

II.

III.

IV.

A)I 
B)II 
C)III 
D)IV

Quizplus · Accepted Answer

To solve the system by graphing, we need to graph both equations on the same coordinate plane and find the point of intersection, which is the solution to the system.

To graph the first equation, we can start by finding its intercepts. When $x = 0$, we have $-2y = 6$, so $y = -3$. When $y = 0$, we have $x = 6$. So we have the intercepts $(0, -3)$ and $(6, 0)$. We can plot these two points and draw a line through them.

To graph the second equation, we can follow the same procedure. When $x = 0$, we have $4y = -12$, so $y = -3$. When $y = 0$, we have $-2x = -12$, so $x = 6$. We can plot the intercepts $(0, -3)$ and $(6, 0)$ and draw a line through them.

The lines intersect at the point $(3, -1)$, which is the solution to the system. Therefore, the answer is B)II.

Solve the system of equations by graphing: {x−2y=6−2x+4y=−12\text { Solve the system of equations by graphing: } \left\{ \begin{array} { c } x - 2 y = 6 \\- 2 x + 4 y = - 12\end{array} \right. Solve the system of equations by graphing: {x−2y=6−2x+4y=−12​

$\text { Solve the system of equations by graphing: } \left\{ \begin{array} { c } x - 2 y = 6 \\- 2 x + 4 y = - 12\end{array} \right.$