Solve the system of equations using the addition method:
2x + 3y = -26
5x - y = 3
A) $x = 1 . y = - 2$
B) $x = 2 \frac { 9 } { 13 } , u = - 1 \cap \frac { 6 } { 13 }$
C) $x = \frac { 2 } { 5 } , y = - 1$
D) $x = - 1 , y = - 8$

Question

Solve the system of equations using the addition method: 
2x + 3y = -26
5x - y = 3
A) $x = 1 . y = - 2$
B) $x = 2 \frac { 9 } { 13 } , u = - 1 \cap \frac { 6 } { 13 }$
C) $x = \frac { 2 } { 5 } , y = - 1$
D) $x = - 1 , y = - 8$

Quizplus · Accepted Answer

To solve the system using the addition method, first make the coefficients of $y$ in both equations the same. Multiply the first equation by 1 and the second equation by 3 to get:$$2x + 3y = -26$$$$15x - 3y = 9$$Adding these equations together to eliminate $y$ gives:$$17x = -17$$$$x = -1$$Substitute $x = -1$ into one of the original equations, for example, the first one:$$2(-1) + 3y = -26$$$$-2 + 3y = -26$$$$3y = -24$$$$y = -8$$So, the solution is $x = -1, y = -8$.

Solve the System of Equations Using the Addition Method x=1.y=−2x = 1 . y = - 2x=1.y=−2

Solve the System of Equations Using the Addition Method $x = 1 . y = - 2$