Suppose ? = 50 and$\sigma$ = 10 for a population.In a sample where n = 100 is randomly taken,90% of all possible sample means will fall between 49 and 51.

Question

Quizplus · Accepted Answer

The standard error of the mean is $\sigma/\sqrt{n} = 10/\sqrt{100} = 1$. For a 90% confidence interval, the z-score is approximately 1.645. The interval is $\mu \pm 1.645 \times 1$, which is 48.355 to 51.645, not 49 to 51.

Suppose ? = 50 And σ\sigmaσ = 10 for a Population

Suppose ? = 50 And $\sigma$ = 10 for a Population