If you were constructing a 99% confidence interval of the population mean based on a sample of n=25 where the standard deviation of the sample S = 0.05,the critical value of t will be
A)2.7969
B)2.7874
C)2.4922
D)2.4851

Question

Quizplus · Accepted Answer

With a 99% confidence level and a sample size of n=25, the degrees of freedom are 24. Using a t-table or calculator, the critical value of t is 2.7969.

If You Were Constructing a 99% Confidence Interval of the Population