SCENARIO 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture.She performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650.The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Scenario 9-6,suppose the engineer had decided that the alternative hypothesis to test was that the mean was less than 650.Then if the test is performed with a level of significance of 0.05,the null hypothesis would be rejected.

Question

Quizplus · Accepted Answer

Since the alternative hypothesis is now one-tailed (less than), the level of significance should be divided by 2, making it 0.025. The calculated p-value of 0.080 is still greater than 0.025, so the null hypothesis cannot be rejected. Therefore, the answer is false.

SCENARIO 9-6 The Quality Control Engineer for a Furniture Manufacturer Is Interested