SCENARIO 10-10
A corporation randomly selects 150 salespeople and finds that 66% who have never taken a self- improvement course would like such a course.The firm did a similar study 10 years ago in which 60% of a random sample of 160 salespeople wanted a self-improvement course.The groups are assumed to be independent random samples.Let $\pi$ 1 and $\pi$ 2 represent the true proportion of workers who would like to attend a self-improvement course in the recent study and the past study,respectively.
-Referring to Scenario 10-10,what is the estimated standard error of the difference between the two sample proportions?
A)0.629
B)0.500
C)0.055
D)0

Question

SCENARIO 10-10
A corporation randomly selects 150 salespeople and finds that 66% who have never taken a self- improvement course would like such a course.The firm did a similar study 10 years ago in which 60% of a random sample of 160 salespeople wanted a self-improvement course.The groups are assumed to be independent random samples.Let  $\pi$ 1 and  $\pi$ 2 represent the true proportion of workers who would like to attend a self-improvement course in the recent study and the past study,respectively.
-Referring to Scenario 10-10,what is the estimated standard error of the difference between the two sample proportions?
A)0.629
B)0.500
C)0.055
D)0

Quizplus · Accepted Answer

The estimated standard error of the difference between the two sample proportions can be calculated using the formula:

SE = sqrt[(p1(1-p1)/n1) + (p2(1-p2)/n2)]

where p1 = proportion in recent study, p2 = proportion in past study, n1 = sample size in recent study, and n2 = sample size in past study.

Plugging in the values, we get:

SE = sqrt[(0.66(1-0.66)/150) + (0.6(1-0.6)/160)]
   = 0.055

Therefore, the estimated standard error of the difference between the two sample proportions is 0.055, which is option C.

SCENARIO 10-10 a Corporation Randomly Selects 150 Salespeople and Finds π\piπ

SCENARIO 10-10
a Corporation Randomly Selects 150 Salespeople and Finds $\pi$