You just deposited $2,500 in a bank account that pays a 4.0% nominal interest rate, compounded quarterly.If you also add another $5,000 to the account one year (4 quarters) from now and another $7,500 to the account two years (8 quarters) from now, how much will be in the account three years (12 quarters) from now?
A) $15,234.08
B) $16,035.88
C) $16,837.67
D) $17,679.55
E) $18,563.53

Question

Quizplus · Accepted Answer

To find the total amount in the account three years from now, we need to calculate the future value of each deposit separately, considering the compound interest formula: $A = P(1 + \frac{r}{n})^{nt}$, where:- $A$ is the amount of money accumulated after n years, including interest.- $P$ is the principal amount (the initial amount of money).- $r$ is the annual interest rate (decimal).- $n$ is the number of times that interest is compounded per year.- $t$ is the time the money is invested for in years.1. For the initial $2,500 deposited, it will compound for 3 years (12 quarters):$$A_1 = 2500(1 + \frac{0.04}{4})^{4*3} = 2500(1 + 0.01)^{12} = 2500(1.01)^{12}$$2. For the $5,000 added after 1 year, it will compound for 2 years (8 quarters):$$A_2 = 5000(1 + \frac{0.04}{4})^{4*2} = 5000(1 + 0.01)^{8} = 5000(1.01)^{8}$$3. For the $7,500 added after 2 years, it will compound for 1 year (4 quarters):$$A_3 = 7500(1 + \frac{0.04}{4})^{4*1} = 7500(1 + 0.01)^{4} = 7500(1.01)^{4}$$Calculating each:- $A_1 = 2500(1.01)^{12} ≈ 2816.89$- $A_2 = 5000(1.01)^{8} ≈ 5418.99$- $A_3 = 7500(1.01)^{4} ≈ 7800$Adding them together:$$Total = A_1 + A_2 + A_3 ≈ 2816.89 + 5418.99 + 7800 ≈ 16035.88$$Therefore, the total amount in the account three years from now will be approximately $16,035.88.

You Just Deposited $2,500 in a Bank Account That Pays