In an interval estimation for a proportion of a population, the value of z at 99.2% confidence is
A) 2.65.
B) 2.41.
C) 1.96.
D) 1.645.

Question

Quizplus · Accepted Answer

For a 99.2% confidence level, we need to find the z-value that corresponds to a tail probability of (1-0.992)/2 = 0.004.

Using a standard normal distribution table or calculator, we can find that the z-value for a tail probability of 0.004 is approximately 2.65. Therefore, the answer is A) 2.65.

In an Interval Estimation for a Proportion of a Population