Of six letters (A, B, C, D, E, and F), two letters are to be selected at random. How many outcomes are possible?
A) 30
B) 11
C) 6!
D) 15

Question

Quizplus · Accepted Answer

When selecting 2 letters out of 6 without regard to order, the number of possible outcomes is calculated using combinations. The formula for combinations is C(n, k) = n! / [k!(n-k)!], where n is the total number of items, and k is the number of items to be chosen. Here, n=6 and k=2, so the calculation is C(6, 2) = 6! / [2!(6-2)!] = (6*5) / (2*1) = 15.

Of Six Letters (A, B, C, D, E, and F)