The total binding energy of is approximately

Question

The total binding energy of  is approximately

Quizplus · Accepted Answer

The total binding energy can be calculated using the mass defect formula: 
Δm = Zmp + (A-Z)mn - m 
where:
Z = atomic number = 27
mp = mass of proton = 1.00728 u 
A = mass number = 60 
mn = mass of neutron = 1.00867 u 
m = mass of nucleus = 59.898 u

Δm = (27)(1.00728 u) + (60-27)(1.00867 u) - 59.898 u 
= 0.99966 u

The total binding energy (BE) can be calculated using E=mc² where c = speed of light and m = Δm × (1.66054 × 10^-27 kg/u) because 1u = 1.66054 × 10^-27 kg

BE = Δm × (1.66054 × 10^-27 kg/u) × (2.998 × 10^8 m/s)^2 / 1.60218 × 10^-13 J/MeV 
= 39.2 MeV

Therefore, the correct answer is (C) 39.2 MeV.

The Total Binding Energy of Is Approximately