If, on the average, each fission reaction of ²³⁵U releases 200 MeV of energy, how many nuclei of ²³⁵U fission every second in a 200-MW reactor?

Question

Quizplus · Accepted Answer

The correct answer is A.Explanation:The energy released per fission is 200 MeV = 200 × 1.6 × 10^-13 J. The power of the reactor is 200 MW = 200 × 10⁶ W. Therefore, the number of fissions per second is:$$\frac{200 imes 10^6 ext{ W}}{200 imes 1.6 imes 10^{-13} ext{ J/fission}} = 6.3 imes 10^{17} ext{ fissions/s}$$

If, on the Average, Each Fission Reaction of 235U Releases

If, on the Average, Each Fission Reaction of ²³⁵U Releases